F(x)=-2x^2-6x+10

Solution for F(x)=-2x^2-6x+10 equation:

(F)=-2F^2-6F+10

We move all terms to the left:

(F)-(-2F^2-6F+10)=0

We get rid of parentheses

2F^2+6F+F-10=0

We add all the numbers together, and all the variables

2F^2+7F-10=0

a = 2; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·2·(-10)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{129}}{2*2}=\frac{-7-\sqrt{129}}{4}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{129}}{2*2}=\frac{-7+\sqrt{129}}{4}
$